Python 生成一个每隔 5 分钟的时间序列，能简化下吗？

如下：
for x in range(0,24):
if len(str(x)) == 1:
x = str(0)+str(x)
for y in range(0,60,5):
if len(str(y)) == 1:
y = str(0)+str(y)
print(str(x)+":"+str(y))

str

len

range

14 条回复 • 2017-07-18 11:52:28 +08:00

GTim

2017-07-09 09:48:04 +08:00

```python
s = ["{:0>2}:{:0>2}".format(i/60,i%60) for i in range(0,86400,5)]
```

GTim

2017-07-09 09:49:52 +08:00

@GTim 把 5 分钟看成秒了，把 86400 换成 1440

hxsf

2017-07-09 09:50:51 +08:00

[str(x) + ':' + str(y) for x in range(0, 24) for y in range(0, 60, 5)] 用推导式啊。。。

hsmocc

2017-07-09 10:21:44 +08:00 via iPhone

["%02d:%02d" %(h,m) for h in range(0, 24) for m in range(0, 60, 5)]

staticor

2017-07-09 11:09:32 +08:00

如果用过 Pandas 的话有方便的时间序列函数.

```python
import pandas as pd
pd.date_range('2017-01-01 01:00:00', '2017-01-01 02:00:00', freq= '5min')

```

Hieast

2017-07-09 11:11:17 +08:00 via Android

arrow 也有专门的时间序列函数

hand515

2017-07-09 13:50:15 +08:00

if len(str(y)) == 1:
为啥不直接 if y< 10: 呢。

raiz

2017-07-09 16:42:10 +08:00

seq = ["%02d:%02d" %(i, j) for i in range(0,24) for j in range(0,60,5)]

hugo775128583

2017-07-09 16:44:02 +08:00 via Android

你需要 rrule

mckelvin

2017-07-10 09:17:45 +08:00

```
import datetime
start_dt = datetime.datetime(2017, 1, 1)
interval = datetime.timedelta(seconds=300)
for i in range(24 * 12):
print (start_dt + interval * i).strftime("%H:%M")
```

svsky

2017-07-10 09:46:24 +08:00

@hsmocc 谢谢

hwsdien

2017-07-10 11:37:43 +08:00

import arrow
start, end = arrow.now().span('day')
print [repr(r) for r in arrow.Arrow.range('minute', start, end) if r.minute % 5 == 0]

xuzixx1001

2017-07-10 16:00:59 +08:00

9 楼+1 dateutil rrule

yylucifer

2017-07-18 11:52:28 +08:00

@GTim 这个不错